Class 11 Physics Oscillations | Displacement |

__Displacement__

- Displacement in periodic motion can be represented by a functionwhich is periodic which repeats after fixed interval of time.

In the above image we can see that motion of an oscillating simple pendulum canbe described in terms of angular displacement θ from the vertical.

In the above image we can see that there is a block whose one end is attached to a spring and another is attached to a rigid wall.x is the displacement from the wall.

In the above figure a blockis attached to a spring, the other end of which is fixed to a rigid wall. The block moves on a frictionless surface. The motion of the block can be described in terms of its distance or displacement x from the wall.

**f (t) = A cos ωt**

As cosine function repeats after 2π so it can be written as

cos (θ) = cos (ωt + 2π) Equation (1)

cos (ωt) = cos (ωt + 2π) (it keep on repeating after 2π)

Let Time Period = T

f (T) = f(t+T) where displacement keeps on repeating after (t+T)

Acos (ωt) = cosω(t+T) = Acos (ωt+ wT)

Acosωt = A cos (ωt+ωT) Equation (2)

From Equation (1) and Equation (2)

ωT= 2π

Or **T=2π /ω**

__Displacement as a combination of sine and cosine functions__

__f (t) = A cos ωt__

f (t) = A sin ωt

f (t) = A sin ωt + A cos ωt

LetA = D cosΦ Equation (3)

B=DsinΦEquation (4)

f (t) =DcosΦ sinωT + DsinΦ cos ωt

D (cosΦ sinωT + sinΦ cos ωt)

(Using sinAcosB + sinBcosA = sin (A+B))

Therefore we can write

f (T)= **D sin (ωT+****Φ)**

From the above expression we can say displacement can be written as sine and cosine functions.

__D in terms of A and B:- __

A^{2 }B^{2 }= D^{2}sin^{2} Φ + D^{2}cos^{2} Φ

A^{2 }B^{2 }= D^{2}

Or D= AB

Φ In terms of A and B

Dividing Equation (4) by (3)

B/A= DsinΦ/Dcos Φ

tan Φ = B/A

Or Φ= tan^{-1} B/A

** Problem:-**Which of the followingfunctions of time represent (a) periodic and (b) non-periodic motion? Give the period foreach case of periodic motion [ω is anypositive constant].

(i) sin ωt + cos ωt

(ii) sin ωt + cos 2 ωt + sin 4 ωt

(iii) e–ωt

(iv) log (ωt)

__Answer:-__

- sin ωt + cos ωt is a periodic function, it can also be written as

2 sin (ωt + π/4).

Now 2 sin (ωt + π/4)= 2 sin (ωt + π/4+2π)

= 2 sin [ω (t + 2π/ω) + π/4]

The periodic time of the function is 2π/ω.

(ii) This is an example of a periodic motion. Itcan be noted that each term represents aperiodic function with a different angularfrequency. Since period is the least intervalof time after which a function repeats itsvalue, sin ωt has a period T_{0}= 2π/ω; cos 2 ωt

has a period π/ω =T_{0}/2; and sin 4 ωt has aperiod 2π/4ω = T_{0}/4. The period of the firstterm is a multiple of the periods of the last

two terms. Therefore, the smallestintervalof time after which the sum of the threeterms repeats is T_{0}, and thus the sum is aperiodic function with aperiod 2π/ω.

(iii) The function e^{–ωt} is not periodic, itdecreases monotonically with increasingtime and tends to zero as t →∞ and thus,never repeats its value.

(iv) The function log (ωt) increases monotonicallywith time t. It, therefore, neverrepeats its value and is a non-periodicfunction. It may be noted that as t →∞,log (ωt) diverges to ∞. It, therefore, cannot represent any kind of displacement.

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