Class 7 Maths Perimeter and Area Squares and Rectangles

Squares and Rectangles

A square is a flat shape with 4 equal sides and every angle is a right angle i.e. 90°.

    Class_7_Maths_Perimeter_And_Area_Square                                                                

In the above figure, ABCD is a square.

Here AB = BC = CD = DA

Each interior angle is 90°.

The Perimeter of square is 4 times the side length. Let a be the length of each side of square.

Now, perimeter of square = 4 * a = 4a

Area of square = side length squared

                            = a * a   

                           = a2

Problem: Find the area of a square park whose perimeter is 320 m.

Solution:

Given: Perimeter of square park = 320 m

=> 4 * side = 320

=> side = 320/4 = 80 m

Now, Area of square park = side * side = 80 * 80 = 6400 m2

Thus, the area of the square park is 6400 m2.

A rectangle is a 4-sided flat shape with straight sides where all interior angles are right angles (90°).

Also opposite sides are parallel and of equal length.

           Class_7_Maths_Perimeter_And_Area_Rectangle                                 

In the above figure, ABCD is a rectangle where

AB = CD and BC = AD

Each interior angle is 90°.

Now, perimeter of a rectangle = 2(length + breadth)

Area of rectangle = length * breadth

Problem: The length and breadth of a rectangular piece of land are 500 m and 300 m respectively.

Find:  (i) Its area.  (ii) The cost of the land, if 1 m2 of the land costs Rs 10,000.

Solution:

Given: Length of a rectangular piece of land = 500 m

and breadth of a rectangular piece of land = 300 m

(i) Area of a rectangular piece of land = Length * Breadth

                                                                   = 500 * 300

                                                                   = 1,50,000 m2

(ii) Since, the cost of 1 m2 land = Rs 10,000

Therefore, the cost of 1,50,000 m2 land = 10,000 * 1,50,000  = Rs 1,50,00,00,000

Triangles as Parts of Rectangles

Let us take a rectangle and cut the rectangle along its diagonal to get two triangles as shown in the figure.

      Class_7_Maths_Perimeter_And_Area_Triangles_As_Parts_Of_Rectangle                     Class_7_Maths_Perimeter_And_Area_Triangles_As_Parts_Of_Rectangle_1                

Superpose one triangle on the other. We find that sum of the areas of the two triangles is the same as the area of the rectangle. Both the triangles are equal in area.

Now, area of each triangle = (1/2) * (Area of the rectangle)

                                                 = (1/2) * (length of rectangle * breadth of rectangle)

Again take a square and divide it into four triangles as shown in the figure. The four triangles are equal in area.

               Class_7_Maths_Perimeter_And_Area_Square_Divided_Into_4_Triangles                                                  

Now, area of each triangle = (1/4) * (Area of the square)

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