Class 9 Maths Constructions Construct a triangle

Construction 5: To construct a triangle given its base, a base angle and the difference of the other two sides

Given the base BC, a base angle, say ∠B and the difference of other two sides AB – AC or AC – AB, you have to construct the triangle ABC. Clearly there are following two cases:

Case (i) : Let AB > AC that is AB – AC is given.

Steps of Construction:

  1. Draw the base BC and at point B make an angle say XBC equal to the given angle.
  2. Cut the line segment BD equal to AB – AC from ray BX.
  3. Join DC and draw the perpendicular bisector, say PQ of DC.
  4. Let it intersect BX at a point A. Join AC. Then ABC is the required triangle

 

Case (ii) : Let AB < AC that is AC – AB is given.

Steps of Construction:

  1. Draw the base BC and at point B make an angle say XBC equal to the given angle.
  2. Cut the line segment BD equal to AC – AB from line BX extended on opposite side of line segment BC.
  3. Join DC and draw the perpendicular bisector, say PQ of DC.
  4. Let PQ intersect BX at A. Join AC. Then, ABC is the required triangle.

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